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Calculate the speed of an electron if it travels in a circular path of radius 50 cm in a magnetic field of 5 × 10^-3 T.(a) 440 × 10^7 m/s(b) 4 × 10^7 m/s(c) 44 × 10^7 m/s(d) 0.4 × 10^7 m/sI got this question in homework.This interesting question is from Motion in Combined Electric and Magnetic Field in section Moving Charges and Magnetism of Physics – Class 12 |
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Answer» RIGHT option is (c) 44 × 10^7 m/s The BEST I can explain: Magnetic force on the electron = CENTRIPETAL force on the electron. evB = \(\frac {mv^2}{R}\), v = \(\frac {eBr}{m}\) v = \(\frac {(1.6 \, \times \, 10^{-19} \, \times \, 5 \, \times \, 10^{-3} \, \times \, 50 \, \times \, 10^{-2})}{(9.1 \, \times \, 10^{-31})}\) v = 43.95 × 10^7 m/s ≈ 44 x 10^7 m/s. |
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