1.

Calculate the speed of an electron if it travels in a circular path of radius 50 cm in a magnetic field of 5 × 10^-3 T.(a) 440 × 10^7 m/s(b) 4 × 10^7 m/s(c) 44 × 10^7 m/s(d) 0.4 × 10^7 m/sI got this question in homework.This interesting question is from Motion in Combined Electric and Magnetic Field in section Moving Charges and Magnetism of Physics – Class 12

Answer» RIGHT option is (c) 44 × 10^7 m/s

The BEST I can explain: Magnetic force on the electron = CENTRIPETAL force on the electron.

evB = \(\frac {mv^2}{R}\),

v = \(\frac {eBr}{m}\)

v = \(\frac {(1.6 \, \times \, 10^{-19} \, \times \, 5 \, \times \, 10^{-3} \, \times \, 50 \, \times \, 10^{-2})}{(9.1 \, \times \, 10^{-31})}\)

v = 43.95 × 10^7 m/s ≈ 44 x 10^7 m/s.


Discussion

No Comment Found

Related InterviewSolutions