Calculate the standard enthalpy change ( in kJ `mol^(-1))` for the reaction , `H_(2)(g) + O_(2)(g) rarrH_(2)O_(2)(g)`, given that bond enthalpy of `H-H,O = O, O-H` and `O-O` ( in `kJ mol^(-1))` are respectively 438, 498,464 and 138A. `-1 30`B. `065`C. `+130`D. `- 334`

Calculate the standard enthalpy change ( in kJ `mol^(-1))` for the rea

1.	Calculate the standard enthalpy change ( in kJ `mol^(-1))` for the reaction , `H_(2)(g) + O_(2)(g) rarrH_(2)O_(2)(g)`, given that bond enthalpy of `H-H,O = O, O-H` and `O-O` ( in `kJ mol^(-1))` are respectively 438, 498,464 and 138A. `-1 30`B. `065`C. `+130`D. `- 334`
Answer» Correct Answer - A `H -H(g)+O=O(g) rarr H-O-O-H(g)` `Delta_(r)H= BE(H-H) + BE(O=O)-[2BE(O-H) +BE(O-H)]` `=438 +498 - [2 xx 464 +138 ]kJ mol^(-1)` `= 936- ( 928+ 138 )= - 130 kJ mol^(-1)`

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Calculate the standard enthalpy change ( in kJ `mol^(-1))` for the reaction , `H_(2)(g) + O_(2)(g) rarrH_(2)O_(2)(g)`, given that bond enthalpy of `H-H,O = O, O-H` and `O-O` ( in `kJ mol^(-1))` are respectively 438, 498,464 and 138A. `-1 30`B. `065`C. `+130`D. `- 334`

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