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Calculate the standard free energy change for the following reaction occurring in the galvanic cell at 298 K. 3Mg(s)+2Al^(3+)(aq)rarr3Mg^(2+)(aq)+2Al(s) Given : E_(Mg^(2+)//Mg)^@=-2.37V and E_(Al^(3+)//Al)=-1.66 V |
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Answer» Solution :(a) `E_(cell)=E_R^@-E_L^@` `=-1.66+2.37` =0.71 V `Delta G^@=-nFE^@ cell` `=-3 times 96500 times 0.71` `=-41090 J Or -411.09 K J` (b) BATTERY cannot be reused. |
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