Calculate the standard internal energy change for the following reactions at `25^(@)C`: `2H_(2)O_(2)(l) rarr 2H_(2)O(l) +O_(2)(g)` `Delta_(f)H^(Theta) at 25^(@)C` for `H_(2)O_(2)(l) =- 188 kJ mol^(-1) H_(2)O(l) =- 286 kJ mol^(-1)`

Calculate the standard internal energy change for the following reacti

1.	Calculate the standard internal energy change for the following reactions at `25^(@)C`: `2H_(2)O_(2)(l) rarr 2H_(2)O(l) +O_(2)(g)` `Delta_(f)H^(Theta) at 25^(@)C` for `H_(2)O_(2)(l) =- 188 kJ mol^(-1) H_(2)O(l) =- 286 kJ mol^(-1)`
Answer» `DeltaH^(Theta) = sum DeltaH^(Theta) ("product") - DeltaH^(Theta) ("reactants")` `=2 (-280) +0 -2(-188)` `=- 572 + 376 =- 196 kJ` `Delta n(g) = 1 - 0 = 1` `DeltaH^(Theta) = DeltaU^(Theta) + Deltan(g) RT :. DeltaU^(Theta) = DeltaH^(Theta) - DeltanRT` `=- 196 -(1xx 8.314 xx 10^(-3) xx 298)` `=198.4775 kJ`

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Calculate the standard internal energy change for the following reactions at `25^(@)C`: `2H_(2)O_(2)(l) rarr 2H_(2)O(l) +O_(2)(g)` `Delta_(f)H^(Theta) at 25^(@)C` for `H_(2)O_(2)(l) =- 188 kJ mol^(-1) H_(2)O(l) =- 286 kJ mol^(-1)`

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