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Calculate the temperature at which rms velocity of a gas is half its value at `0^(@)C`, pressure remaining constant

Answer» Here, `T_(0)=0^(@)C = (0+273)K = 273 K`
`T_(2) = ? upsilon_(2) = 1/2 upsilon_(1)`
As , `(upsilon_2)/(upsilon_1) = sqrt((T_2)/(T_1)) = 1/2 `
`T_(2) = sqrt((T_1)/(4)) = 273/4 = 68.25 A`
`=(68.25 - 273)^(@)C = -(204.75)^(@)C`.


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