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Calculate the tension in a string that whirls a 2 kg toy in a horizontal circle of radius 2.5 iv when it moves at 3 m/s. |
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Answer» Mass of the toy m = 2 kg ; Radius of the circle = 2.5 m ; Speed of the toy = 3 m/s As the toy is moving in a horizontal circle, the necessary centripetal force is provided due to the tension in the string. ∴ The centripetal force , Fc = \(\frac{mv^2}{R}= \frac{2\,\times\,3\,\times3}{2.5}=\frac{18}{2.5}\) = 7.2 N |
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