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Calculate the time required for 60% of a sample of radon undergo decay. Given T_(1//2) of radon = 3.8 days. |
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Answer» Solution :Hereconsider `R_(n) - 222` with a half life of 3.823 days. From decay equation, Current amount = `"Initial amount" XX (2)^(-n)` `N = N_(0) (2)^(-n)` `(N)/(N_(0)) = (2) ^(-t)/(T_(1/2))` `log((N)/(N_(0)) = log (2) xx (-(t)/(T_(1/2)))` `log((N)/(N_(0)))/(log(2)) = (-(t)/(T_(1/2)))` `t = (log(0.4))/(log(2)) xx (-3.823)` Time t = `5.05` days. |
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