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Calculate the torque on a 500 turn rectangular coil of length 20 cm and breadth 10 cm, carrying a current of 30 A, when placed making an angle of 60^o with a magnetic field of 0.5 T?(a) 625 Nm(b) 125 Nm(c) 75 Nm(d) 25 NmThis question was posed to me in class test.The above asked question is from Torque on Current Loop & Magnetic Dipole in section Moving Charges and Magnetism of Physics – Class 12

Answer»

The correct OPTION is (C) 75 Nm

Explanation: Torque = NIBA cosθ [Angle between field and plane of coil].

Torque = 500 × 30 × 0.5 × 200 × 10^-4 × cos (60)

Torque =75 Nm.

Therefore, the torque is 75 Nm.



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