1.

Calculate the total kinetic energy of one kilo mole of Oxygen gas at `27^(@)C`

Answer» Since oxygen is a diatomic gas, its molecules have 5 degrees of freedom. Therefore, the total kinetic energy of molecule of Oxygen is `(5)/(2)k_(B)T`.
As, 1kg-mole of Oxygen has N molecules, the total kinetic energy of one kg-mole of Oxygen is temperature T is `(5)/(2)xx8.31xx300`
`=6.23xx10^(6)` Joule/kg-mole


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