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Calculate the total number of degree of freedom possessed by 10 c.c. of hydrogen gas at N.T.P |
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Answer» Correct Answer - `1.34375 xx 10^(21)` Number of hydrogen molecules in `22400` c.c. `= 6.02 xx 10^(23) at NTP` `:.` Number of hydrogen molecules in `10 c.c.` `=(6.02 xx 10^(23) xx 10)/(22400)` at NTP As hydrogen is diatomic gas, each molecule has 5 degree of freedom. `:.` Total no. of degree of freedom `= (5 xx 6.02 xx 10^(23) xx10)/(22400) = 1.34375 xx 10^(21)` |
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