InterviewSolution
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InterviewSolution
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Calculate the total work done by the gas in the process. (given ln2=0.693). |
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Answer» Total work done by gas, WTotal = WAB + WBC + WCA WAB = nRT ln 4V/V = 2nRT ln2 = 2PV ln2. Also PAVA = PBVB (As AB is an isothermal process) or, PB = PAVA/VB = PV/4V = P/4. In the step BC, the pressure remains constant. Hence the work done is, WBC = P/4(V − 4V) = −3PV/4. In the step CA, the volume remains constant and so the work done is zero. The net work done by the gas in the cyclic process is W = WAB + WBC + WCA = 2PVln2 − 3PV/4 + 0 Hence, the work done by the gas is 0.636 PV. |
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