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Calculate the value of the resistance R in the circuit shown in Fig. so that the current in the circuit is 0.2 A. What would be the potentialdifference between points B and E ? |
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Answer» Solution :In the circuit shown here resistance of 5`Omega`joinedbetween B and C, and resistance of 10`Omega`joined between C and D are in series and FORM a resistance of 15`Omega` . Now this resistance of 15`Omega`is in PARALLEL arrangement with resistances of 10`Omega` and 30`Omega`between the points B and E. Hence equivalent resistance R. between B and E points is given by `(1)/(R.) = 1/15 + 1/10 + 1/30 = 1/5 rArr R.= 5Omega` So the equivalent circuit may be REDRAWN as in Fig.Applying Kirchhoff.s law to the circuit BEFAB, we have` -0.2 xx 5 - 0.2 xx R-3-0.2 xx 15+8=0 ` ` R = 5Omega` and potential difference between B and E, `V_B - V_E = 0.2 xx 5 = 1.0 V` |
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