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Calculate the value of universal gas constant at `STP`.

Answer» Universal gas constant is given by ` R=(PV)/(T)`
One mole of all gases at ` S.T.P.` occupy volume `V = 22.4` litre = ` 22.4xx10^(-3)m^(3)`
`P = 760` mm of Hg = ` 760xx10^(-3)xx13.6xx 10^(3) xx9.80 N m^(-2) T=273.16 K`
`therefore R = (760xx10^(-3) xx 13.6 xx 10^(3)xx 9.80 xx 22.4 xx 10^(-3))/273.16 = 8.314 J mol^(-1)K^(-1)`


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