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Calculate the voltage drop across 5 Omega resistance and current passing through the zener diode for the circuit given below: |
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Answer» Solution :Since the voltage across the zener DIODE `V_(2)=50"volt"` `THEREFORE`Voltage drop across `5Omega` resistor =120-20=70 volt `therefore`Current through load resistor of `10kOmega` `I_(L)=(V_(z))/(R_(L))=(50)/(10kOmega)=5XX10^(-3)amp` Therefore ,current through the Zener diode `I_(z)=I-I_(L)=14-5xx10^(-3)` amp=13.996 amp. |
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