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Calculate the volume occupied by 16gram `O_(2)` at `300K` and `8.31 Mpa` if `(P_(C)V_(C))/(RT_(C))=3//8` and `(P_(r)V_(r))/(T_(r))=2.21` ( Given `:R=8.314 MPa//K-mol )`A. `120.31mL`B. `124.31mL`C. `248.62mL`D. none of these |
Answer» Correct Answer - 2 `(PV_(m))/(RT)=(3)?(8)xx2.21," "V_(m)=((3)/(8)xx2.21)xx(RT)/(P),` `V_(m)=(3)/(8)xx2.21xx(8.314xx300)/(8.314)=124.31mL` |
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