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Calculate the volume of hydrogen liberated at `27^(@)C and 760mm` pressure by treating 1.2g of magnesium with excess of hydrochloric acid. |
Answer» The balanced equation is `underset(24g)underset(1"mol")(Mg)+2HCl to MgCl_(2)+underset(22.4"litre of NTP")underset(1"mol")(H_(2))` 24g of Mg liberates hydrogen=22.4litre 1.2g Mg will libertes hydrogen=`(22.4)/(24)xx1.2=1.2"litre` Volume of hydrogen under give condition can be calculated by applying `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `{:(,P_(1)=760mm,P_(2)=760mm),(,T_(1)=273K,T_(2)=(27+273)=300K),(,V_(1)=1.12"litre",V_(2)=?):}` `V_(2)=(760xx1.12)/(273)xx(300)/(760)=1.2308"litre"` |
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