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Calculate the volume strength of `H_2O_2` solution if 50 " mL of " this diluted solution required 40 " mL of " `(M)/(60)` `K_2Cr_2O_7` solution in presence of `H_2SO_4` for complete reaction. |
Answer» `H_2O_2-=Cr_2O_7^(2)` `(n=2)(n=6)` `mEq-=mEq` `N_1V_1-=N_2V_2` `N_1xx20-=(1)/(60)xx6xx40` `N(H_2O_2)=(4)/(20)=0.2N` The normality of the 50 " mL of " `H_2O_2` should be twice the normality of 20 " mL of " the diluted solution of `H_2O_2`. Since the volume of `H_2O_2` solution has doubled. `(50 " mL of " H_2O_2+50" mL of " H_2O=` 100 " mL of " solution of `H_2O_2`) `N(H_2O_2) of 50 " mL of " H_2O_2=0.2xx2=0.4N` Volume strength of `H_2O_2=5.6xx0.4=2.24` volume of `O_2` |
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