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Calculate the wavelength of an electron accelerated under a p.d of 150 V. |
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Answer» SOLUTION :`V=150V,m=9.1xx10^-31kg` `E= 1.6 xx10^-19 C,h=6.62xx10^-34Js` `lambda=h/SQRT(2meV` `=(6.62xx10^-34)/sqrt(2xx9.1xx10^-31xx1.6xx10^-19xx150)=1xx10^-10m=1A^@` |
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