1.

Calculate the wavelength of an electron accelerated under a p.d of 150 V.

Answer»

SOLUTION :`V=150V,m=9.1xx10^-31kg`
`E= 1.6 xx10^-19 C,h=6.62xx10^-34Js`
`lambda=h/SQRT(2meV`
`=(6.62xx10^-34)/sqrt(2xx9.1xx10^-31xx1.6xx10^-19xx150)=1xx10^-10m=1A^@`


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