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Calculate the wavelength of the first spectral line in the corresponding Lyman series of the hydrogen atom. |
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Answer» Solution :For first SPECTRAL line of Lyman SERIES, `n_(F)=1,n_(i)=2` `:.` Wavelength `(1)/(lamda)=R((1)/(n_(f)^(2))-(1)/(n_(i)^(2)))` or `(1)/(lamda)=R[(1)/(1^(2))-(1)/(2^(2))]` `implies(1)/(lamda)=R[1-(1)/(4)]` or `lamda=(4)/(3R)` `("":.R=` Rydberg constant `=1.0973xx10^(7)m^(-1)`) `:.lamda=(4)/(3xx1.0xx10^(7))` `=1210Å` |
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