1.

Calculate the weight of HI obtained by the reaction of 62 g of red phosphorus with iodine in presence of water.

Answer» `P_(4)+6I_(2) to 4PI_(3)`
`PI_(3)+3H_(2)O to H_(3)PO_(3)+3HI]xx4`
`P_(4)+6I_(2)+12H_(2)O to 4H_(3)PO_(3)+12HI`
`31xx4 " " 12 (1+127)`
`=124 g " " =1536 g`
124 g or red phosphorus form HI =1536 g
62 g of red phosphorus form HI`=((1536g))/((124 g))xx(62g)=768g`


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