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Calculate the weight of HI obtained by the reaction of 62 g of red phosphorus with iodine in presence of water. |
Answer» `P_(4)+6I_(2) to 4PI_(3)` `PI_(3)+3H_(2)O to H_(3)PO_(3)+3HI]xx4` `P_(4)+6I_(2)+12H_(2)O to 4H_(3)PO_(3)+12HI` `31xx4 " " 12 (1+127)` `=124 g " " =1536 g` 124 g or red phosphorus form HI =1536 g 62 g of red phosphorus form HI`=((1536g))/((124 g))xx(62g)=768g` |
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