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Calculate the weight of `N_(2)` in `6.24` litre cylinder at `27^(@)C` and `750 mm hg` `(R =0.0821` litre atm `K^(-1) mol^(-1))` . |
Answer» Correct Answer - 7<br>Given `V =6.24 litre, P = (750)/(760)atm`<br> `T = 27 + 273 = 300K, m = 28`<br> Now `PV = (w)/(m0RT)`<br> `:. W = (PVm)/(RT) = (750 xx 6.24 xx 28)/(760 xx 0.0821 xx 300) =7g` . | |