Calculate the work done by `1.0 mol` of an idela gas when it expands from `10atm` to `2atm` at `27^(@)C`.

Calculate the work done by `1.0 mol` of an idela gas when it expands f

1.	Calculate the work done by `1.0 mol` of an idela gas when it expands from `10atm` to `2atm` at `27^(@)C`.
Answer» Process is reversible, since the pressure is decreased from `10 atm` to `2atm` in one step. `w_(("irr,isotherm)) =- P_(ex)(V_(2)-V_(1))` `=- P_(ex) ((nRT)/(P_(2))-(nRT)/(P_(1)))` `=- P_(ex) xx nRT ((1)/(P_(2))-(1)/(P_(1)))` `= - 2xx1xx 0.082 xx 300 ((1)/(2)-(1)/(10))` `=- 2 xx 0.082 xx 300 xx (4)/(10)` `= 19.68 L-atm` `= 119.68 xx 101.3J =- 1993.58J` (since `1L-atm = 101.3J)`

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Calculate the work done by `1.0 mol` of an idela gas when it expands from `10atm` to `2atm` at `27^(@)C`.

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