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Calculate the work done during isothermal reversible expansion expansion of one mol of an ideal gas from 10 atm to 1 atm at 300K. |
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Answer» Number of moles of ideal gas (n) = 1, Initial pressure `(P_(1))=10` atm, Final pressure `(P_(2))=1` atm Constant absolute temp (T) = 300 K, Gas constant (R )= 2 cal/mol. `therefore` Work done ofr isothermal reversible expansion of an ideal gas `W=-2.303 "nRT log" (P_(1))/(P_(2))=-2.303xx1xx2xx300xx"log"_(10)(10)/(1)=-1381.8` calories |
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