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Calculate the work done (in J) when 4.5 g of `H_(2)O_(2)` reacts against a pressure of 1.0 atm at `25^(@)C` `2H_(2)O_(2)(l)rarr O_(2)(g) +2H_(2)O(l)`A. `-1.63 xx 10^(2)`B. `4.5 xx 10^(2)`C. `3.2 xx 10^(2)`D. `-6.1 xx 10^(2)` |
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Answer» Correct Answer - A `w=-Deltan_(g)RT=(-4.5 )/(34xx2)xx8.314 xx298`, `w=-163.9 J` |
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