InterviewSolution
Saved Bookmarks
| 1. |
Calculate the work done when 50 g of iron is dissolved in HCl at `25^(@)C` in (i) a cloed vessel and (ii) an open beaker when the atmospheric pressure is 1atm. |
|
Answer» (i) When the reactiion is carried in a closed vessel, the change in volume is zero. Hence, the work done by the system will be zero. (ii) when iron dissolves in HCl, hydrogen is produced. `undersetunderset(50g)(56g)(Fe)+2HCltoFeCl_(2)+undersetunderset((1)/(56)xx50"Mole")(1" mole")(H_(2))` Volume of hdyrogen produced at `25^(@)C` `=(nRT)/(P)=(50)/(56)xx(0.0821xx298)/(1)=21.84L` this is equal to volme change when the reaction is carried in open beaker. Work done by the system `=-PDeltaV=-1.0xx21.84` `=-21.84"Litre"-atm =-2212.89J` |
|