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Calculatethe wavelenght of H_(alpha)linein Balmerseries of hydrogen . GivenRydberg constant R = 1.097 xx 10^(-7) m^(-1) |
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Answer» Solution :We knowthatwave numbers and wavelengths of differentspectral LINES of Balmer SERIES aregiven by . `(1)/(lambda) = bar(v) = R [(1)/(2^(2)) - (1)/(n^(2))]` `therefore ` Forfirst line of Balmerseries`(1)/(lambda) = R [(1)/(2^(2)) - (1)/(3^(2))] = (5R)/(36)` `rArr "" lambda = (36)/(5R) = (36)/(5 xx 1.097 xx 10^(7)) = 6.563 xx 10^(-7) m = 656.3 nm` |
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