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Calulate the weight of lime `(CaO)` obtained by heating `300 kg` of `90%` pure limestone `(CaCO_(3))`. |
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Answer» `100 kg` impure sample has pure `CaCO_(3)= 90 kg` `:. 300 kg` impure sample has pure `CaCO_(3)` `=(90xx300)/(100)= 270 kg` `CaCO_(3)rarrCaO+CO_(2)` `:. 100 kg CaCO_(3)` gives `CaO= 56 kg` `:. 270 kg CaCO_(3)` gives `CaO=(56xx270)/(100)= 151.120 kg` |
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