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Can any Genius solve this. It's a brilliant question from IMO (INTERNATIONAL MATHS OLYMPIAD) Best for Brainliest |
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Answer» of all we find the area of the RECTANGLE .☃️ Area of rectangle = (24 × 15) cm²→ Area of rectangle = 360 cm² .✴️ It is clearly that,✔️ Area of the shaded region = Area of the rectangle - [Area of (∆ADF + ∆ABE + ∆CEF)](i) Area of ∆ADF ;-∆ADF is a right angled triangle .☃️ Area of ∆ADF = 1/2 × AD × DF→ Area of ∆ADF = 1/2 × 15 × 12→ Area of ∆ADF = 15 × 6→ Area of ∆ADF = 90 cm²(ii) Area of ∆ABE ;-∆ABE is a right angled triangle .BE = BC - CE = 15 - 8 = 7 cm☃️ Area of ∆ABE = 1/2 × AB × BE → Area of ∆ABE = 1/2 × 24 × 7→ Area of ∆ABE = 12 × 7→ Area of ∆ABE = 72 cm²(III) Area of ∆CEF ;-∆CEF is a right angled triangle .CF = DC - DF = 24 - 12 = 12 cm²☃️ Area of ∆CEF = 1/2 × CE × CF→ Area of ∆CEF = 1/2 × 8 × 12→ Area of ∆CEF = 4 × 12→ Area of ∆CEF = 48 cm²⚡ Therefore,Area of the shaded region = 360 - (90 + 72 + 48)→ Area of the shaded region = 360 - 210→ Area of the shaded region = 150 cm² ∴ The area of the shaded region is '150cm²' . |
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