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Can any one answer this it's urgent pleaseIn ∆PQR,if PQ>pR and bisectors of angle Q and angle R intersect at S. show that SQ >SR.​

Answer»

Answer:

In △PQR,PQ>PR

⇒∠PRQ>∠PQR(Angle OPPOSITE to longer side is greater)

⇒

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∠PRQ>

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∠PQR

⇒∠SRQ>∠SQR SINCE RS and QS are the bisectors of ∠PRQ and ∠PQR

In △SQR,∠SRQ>∠SQR

⇒SQ>SR since side opposite to greater angle is longer.


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