Can anyone do it ?Plz help me

1.	Can anyone do it ?Plz help me
Answer» Given - $\angle \: p = \frac{1}{2} \angle \: q$ To FIND - The VALUES of p and q Solution - We know that p+q=180°[Linear PAIR]........ 1) Now putting the VALUE of p we will get $\frac{1}{2}\angle \: q + \angle \: q = 180$ $\frac{1 + 2}{2}\angle q = 180$ $\frac{3}{2} \angle \: q = 180$ $3 \: \angle \: q = 180 \times 2$ $\angle \: q = \frac{180 \times 2}{3}$ $\angle \: q = 120$ Now putting the value of q in equation 1) we will get - $\angle \: p + \angle \: q = 180$ $\angle \: p + 120 = 180$ $\angle \: p = 180 - 120$ $\angle \: p = 60$ $\therefore \: The \: value \: of \: \angle \: p \: is \: {60}^{0} \: and \: \\ value \: of \: \angle \: q \: is \: {120}^{0}$

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