1.

Can anyone please explain this portion? My 100 th question​

Answer»

ANSWER:

Step-by-step explanation:

& = intersection

n(a & b) + n(a-b)  = n(a) --> 1

n(a&b) + n(b-a) = n(b) --> 2

n(a UNION b) = n(a-b) +n(a & b) + n(b-a)   #from figure

add and subtract n(a&b) to this

=> n(a-b) +n(a & b) + n(b-a) + [n(a &b) - n(a &b)]

doing this enables u to use 1 and 2

=> [n(a-b) + n(a &b)] + [n(b-a) +(n(a &b)] - n(a & b))

=> n(a) +n(b) - n(a & b)

which is the result


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