1.

Can anyone please tell me the answer​

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Answer:

hey here is your answer

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Step-by-step explanation:

so here for an adjoining circle

angle dbc intercepts arc cd on circumference of circle

so here so using inscribed angle theorem we get angle dbc=1/2×m(arc cd)

ie 60=1/2×m(arc cd)

ie m(arc cd)=120 degrees (1)

MOREOVER similarly angle ADB and angle bdc intercepts arc AB and bc RESPECTIVELY on circumference of circle

again apply same theorem ie inscribed angle theorem

we get

angle adb=1/2×m(arc ab)

angle bdc=1/2×m(arc bc)

ie 30=1/2×m(arc ab)

30=1/2×m(arc bc)

m(arc ab)=60

m(arc bc)=60

so now by arc addition property

we get

major m(arc ABC)=m(arc ab)+m(bc)

=60+60

=120 degrees (2)

so from (1) and (2)

we get

m(arc cd)=m(major arc abc)

thus proved



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