1.

Can one consider the temperature 20 and 30K as low for to 0.226 and 0.760J//(mol.K)?

Answer»

Solution :At LOW temperature `C prop T^(3)`. This is also a test of the "lowness" of the temperature We see that
`((C_(1))/(C_(2)))^(1//3)=1.4982~~ 1.5=(T_(1))/(T_(2))=(30)/(20)`
THUS `T^(3)` law is OBEYED and `T_(1),T_(2)` can we REGARDED low.


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