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Can the mean of a binomial distribution be less than its variance? |
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Answer» Let X be a binomial variate with parameters in and p. Mean = np Variance = npq Mean - Variance = np – npq = np(1 - q) = np2 > 0 So, Mean – Variance > 0 ⇒ Mean > Variance So, mean can never be less than variance. |
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