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Capacitance of a capacitor 100 mu F. The work is done for depositing chargc 8 xx 10^(-18) C on it will be .........

Answer»

`16.10^(23) J`
`3.1xx10^(-26)` J
`4xx10^(-10)` J
`32 xx10^(-32)` J

Solution :`W = U_(2) -U_(1)`
`= (Q^(2))/(2C) -0`
`=((8xx10^(-18))^(2))/(2xx100xx10^(-6))=(64xx10^(-36+4))/(2)`
`:. W = 32 xx10^(-32)` J


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