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Capacitance of a capacitor made by a thin metal foil is 2 muF. If the foil is foilded with paper of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of paper is 400 mm, the length of foil will be |
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Answer» 0.34 m `rArr 2XX10^(-6) = (2.5xx8.85xx10^(-12)(lxx400xx10^(-3)))/(0.01xx10^(-3))` `l = 33.9 m` |
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