Capacitance of capacitor is 2pE. Electric field inside capacitor is changing with the rate of 10^(12)Vs^(-1). Then displacement current is …….. A.

Capacitance of capacitor is 2pE. Electric field inside capacitor is ch

1.	Capacitance of capacitor is 2pE. Electric field inside capacitor is changing with the rate of 10^(12)Vs^(-1). Then displacement current is …….. A.
Answer» 2 3 6 9 Solution :`I=(d theta)/(DT)` but, PUTTING Q = CV `=(d)/(dt)[CV]=C.(DV)/(dt)` `=2xx10^(-12)xx10^(12)` `THEREFORE I=2A`

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Capacitance of capacitor is 2pE. Electric field inside capacitor is changing with the rate of 10^(12)Vs^(-1). Then displacement current is …….. A.

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