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Capacitance per unit area at no reverse bias is 2 pF/cm^2. For a step graded diode of area 5cm^2, what is net capacitance at 99 V reverse bias voltage?(a) 2pF(b) 5pF(c) 0.1pF(d) 1pFThis question was posed to me in final exam.This key question is from Transition Capacitance in division Diode Circuit of Analog Circuits

Answer» RIGHT answer is (d) 1pF

The explanation: CO=2pf/cm^2

C = CO*A/(1 + 99)^0.5 = 2pF X 5/10 = 1pF.


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