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Capacitance per unit area at no reverse bias is 2 pF/cm^2. For a step graded diode of area 5cm^2, what is net capacitance at 99 V reverse bias voltage?(a) 2pF(b) 5pF(c) 0.1pF(d) 1pFThis question was posed to me in final exam.This key question is from Transition Capacitance in division Diode Circuit of Analog Circuits |
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Answer» RIGHT answer is (d) 1pF The explanation: CO=2pf/cm^2 C = CO*A/(1 + 99)^0.5 = 2pF X 5/10 = 1pF. |
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