Saved Bookmarks
| 1. |
Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is 8.0 xx 10^3 Nm^2//C. (a) What is the net charge inside the box ? (b) If the net outward flux through the surface of the box were zero, could you conclude that there were no charges inside the box ? Why or Why not ? |
|
Answer» Solution :(a) According to Gauss.s law, net electric flux PASSING through any closed surface, enclosiri net charge q in vacuum (or free space) is, `phi = q/epsilon_(0)` `therefore q = phiepsilon_(0)` `= 8 xx 10^(3) xx 8.85 xx 10^(-12)` `therefore q = 7.08 xx 10^(-8)` C (b) Again, `phi^(.) = q^(.)/epsilon_(0)` Here, `phi. = 0 rArr q. =0` GIVEN box MIGHT contain EQUAL amount o unlike CHARGES whose net charge is zerc Thus, when q. = 0, it is not necessary that i does not contain any charge. |
|