1.

CH_3 -CH_2 - CH_2- Br overset(Alc.KOH)toCH_3-CH =Br overset(HBr)to CH_3 - overset(Br) overset(|)(CH) -CH_3

Answer»

X = dilute NaOH, `20^@C` , Y = HBr/acetic acid, `20^@C`
X = CONCENTRATED alcoholic NaOH, `80^@C` , Y = HBr/acetic acid, `20^@C`
X = dilute NaOH, `20^@C` , Y` = HBr//CH_3 , 0^@C`
X = Concentrated alcoholic NaOH, `80^@C , Y = HBr//CHCl_3,0^@C`

Solution :`CH_3 - CH_2 - oversetunderset(|)(Br)(C )H_2 underset(-KBr)overset(ALC KOH)(to) H_3C- CH = CH_2 overset(HBr)(to) H_3C - oversetunderset(|)(Br)(C )H - CH`


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