`CH_3OH`, methanol can be prepared from CO and `H_2`. `CO(g)+2H_2(g)hArr CH_3OH(g)` The value of `K_p` at 500 K is `6.23xx10^(-3)` When total pressure (in atm) at equilibrium is required to convert 25% of CO to `CH_3OH` at 500 K if CO and `H_2` comes from `CH_4(g)+H_2O(g) to CO(g)+3H_2(g)` Given your answer excluding decimal places.

`CH_3OH`, methanol can be prepared from CO and `H_2`. `CO(g)+2H_2(g)hA

1.	`CH_3OH`, methanol can be prepared from CO and `H_2`. `CO(g)+2H_2(g)hArr CH_3OH(g)` The value of `K_p` at 500 K is `6.23xx10^(-3)` When total pressure (in atm) at equilibrium is required to convert 25% of CO to `CH_3OH` at 500 K if CO and `H_2` comes from `CH_4(g)+H_2O(g) to CO(g)+3H_2(g)` Given your answer excluding decimal places.
Answer» Correct Answer - 10

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