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Change in entropy for reaction `2H_(2)O_(2)(l)rarr2H_(2)O(l)+O_(2)(g)` if heat of formation of `H_(2)O_(2)(l)` and `H_(2)O(l)` are `-188` and `-286KJ//mol` respectively isA. `-196KJ//mol`B. `+196KJ//mol`C. `+948KJ//mol`D. `-948KJ//mol` |
Answer» Correct Answer - D `2H_(2)O_(2)(l)rarr2H_(2)O(l)+O_(2)(g)" " DeltaH=`? `DeltaH=[(2xxDeltah_(f)` of `H_(2)O(l)+(DeltaH_(f)` of `O_(2))` `[(2xxDeltaH_(f)` of `H_(2)O_(2)(1))]` `=[(2xx-286)+(0)-(2xx-188)]` `=[-572+376]=-196KJ//mol` |
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