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Change in internal energy when `4 kJ` of work is done on the system and `1 kJ` of heat is given out of the system isA. `+1 kJ`B. `-5 kJ`C. `+5k J`D. `+3 kJ` |
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Answer» Correct Answer - D `DeltaU=q+w=(-1 kJ)+4kJ=+3kJ` |
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