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Change in polar form of (1-√-3) |
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Answer» Answer: Step-by-step explanation: Explanation: LET Z=1−(√3)i ; Modulus |Z|=(√12+(−√3)2)=2;tanθ=√−31ortanθ=√−3 Argument θ=tan−1(√−3)=−600or3000 |
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