1.

Charge over a nonconducting ring is distributed so that the linear charge density varies as lambda = lambda_0sin theta. What is the direction of force on a charge q_0 placed at the center?

Answer»

along 1 if `q_0` is positive and 2 if `q_0` is NEGATIVE.
along 2 if `q_0` is positive and 1 if `q_0` is negative.
along 3 if `q_0` is positive and 4 if `q_0` is negative.
along 4 if `q_0` is positive and 3 if `q_0` is negative.

Solution :For `thetalethetalt2pi,LAMBDA` is negative and symmmetrically distributed about `y-`axix.
HENCE direction of electric Beld `E_("NE")` at `O` due to CHARGE distribution is in downward direction, If `q_(0)` is `


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