1.

Charge passing through a conductor carrying current is given by Q = 5t^(2) + 3t +1, How much amount of current will pass in t = 5 s ?

Answer»

9A
49 A
53 A
151 A

Solution :53 A
I = `(DQ)/(dt ) = 10 `By TAKING t = 5 in t + 3
I = 53 A


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