1.

Charge passing through the cross-section of a conductor h given by Q = B' + A' t^(2). What will be the current in ampere at lime t = 10 s ?

Answer»

5 A'
10 A'
20 A'
40 A'

Solution :20 A.
I= `(dQ)/(dt ) = (d)/(dt)(B. + A. t^(2)) `
`therefore I = 0 + 2A.t `
`therefore I = 2A. XX 10 = 20 A.`


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