InterviewSolution
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InterviewSolution
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Charges of +2 +2, and-2 muCrespectively are placed at the vertices of an equilateral triangle of side0.3meach in Find the net forces experienced by each charges. |
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Answer» Solution :Here AB = AC =BC =0.3 and `q_A =q_B =+ 2mu C = 2xx 10 ^(-6) C and q_C =- 2muC =-2 xx 10 ^(-6)C ` Thus , it is clear that mutual force of attraction/repulsion between any two charges have equal MAGNITUDE GIVEN by ` ""F= |oversetto (F_(AB))|=|oversetto (F_(CB)) |=(9xx 10 ^(9) xx (2xx 10 ^(-6))^(2)) /( (0.3)^(2)) =0.4 N ` Direction of these forces have been SHOWN in (a)As angle between `oversetto (F_(CA)) and oversetto (F_(CB)) is 60^(@) ` , hence `|oversetto (F_C) |=2F _(CA) cos ""( (60)/( 2))^(@) ` ` ""=2 xx0.4 xx (sqrt( 3))/(2)` ` = 0.69 N and ` the force is `TT `to AB. (b)As angle between `oversetto (F_(AB))and oversetto (F_(AC))is 120 ^(@) `, hence `|oversetto (F_A) |2F_(AB) cos 60^(@) = 2xx 0.4 xx (1)/(2)= 0.4 N ` and the force makes an angle ` 60^(@) ` from line AC. (c)As in (b)force `|oversetto (F_B)|=0.4 N `inclined at an angle of ` 60^(@) `from line BC. ` (##U_LIK_SP_PHY_XII_C01_E10_022_S01.png" width="80%"> |
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