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charges of an electron in esu determined as4.806 xx 10^(-10)esu. Show that1C = 3xx 10 ^(9)esu |
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Answer» Solution :a . `1C =3xx10 ^(9) esu "" because lesu (1)/( 3xx10 ^(9) C ` NUMBER of electron in 1C =` 6.25 xx 10 ^(12) ` ` because ` Number of electron in 1 esu ` = (1)/( 3xx10 ^(9)) xx 6.25 xx 10 ^(18)- 208 xx10 ^(9) ` Number of electronsin 1 esu ` = (1)/( 3xx10 &(9) ) xx 6.25 xx10 ^(18) ` ` because ` charges esu is ` 6.25 xx10 ^(6) xx 4.806 xx10 ^(10) ` ` therefore 1C =6.25 xx10 ^(18)xx 4.806 xx 10 ^(10)= 3xx 10 ^(9) ` esu of charges. |
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