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Check that the ratio ke^(2)//Gm_(e) m_(p) is dimenionless, Look up a tableof Physical Constants and determinethe valueof thisi ratio. What does the ratio signigy ? |
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Answer» <P> Solution :`(ke^(2))/(G m_(e) m_(p)) = ([N m^(2) C^(-2)] [C^(2)])/([N m^(2) KG^(-2)] [kg] [kg]) = 1 = (M^(@) L^(@)T^(@))``:.` The GIVEN ratio dimenesionless.using`k = 9xx10^(9) N m^(2) C^(-2), e = 1.6xx10^(-19)C, G = 6.67xx10^(-11) N m^(2) kg^(-2)`, `m_(e) = 9.1xx10^(-31) kg, and m_(p) = 1.66xx10^(-27) kg`, we get ,`(ke^(2))/(G m_(e) m_(p)) = 2.29xx10^(39)` This is the ratio of electrostaticforce to gravitationalforce between anelectronand a proton. |
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